Back to Physics Topics
JEE Advanced Focus Reading Time: 20 min 5 Complex Problems

JEE Advanced PYQ Deep Dive: The Toughest Wave Optics Problems

Break down complex multi-concept problems with step-by-step thought processes and strategic approaches.

2015-2023
PYQs Covered
100%
Advanced Level
15+
Concepts Integrated
45min
Avg. Solve Time

Why This Deep Dive Matters

Wave Optics in JEE Advanced tests your ability to integrate multiple concepts and apply them to unfamiliar situations. These 5 problems represent the most challenging patterns from 2015-2023:

  • Multi-slit interference with phase differences
  • Doppler effect in light with relative motion
  • Polarization + interference combined problems
  • Diffraction grating with missing orders
  • Young's double slit with medium changes
JEE Advanced 2021 Hard

Problem 1: Three-Slit Interference with Phase Difference

Three parallel slits separated by distance d are illuminated by light of wavelength λ. The middle slit has a phase advance of π/2 relative to the other two. Find the intensity at an angle θ where the path difference between adjacent slits is Δ.

🧠 Thought Process Breakdown:

Step 1 - Identify the twist: This isn't standard 3-slit interference due to the phase difference in the middle slit.

Step 2 - Electric field approach: Treat each slit as a source of electric field with appropriate phase.

Key Concept: Resultant intensity depends on vector sum of individual electric fields

Step 3 - Phase calculation: Standard phase due to path difference + additional phase for middle slit.

📝 Solution Approach:

Step 1: Let phase difference between adjacent slits due to path difference be $\phi = \frac{2\pi}{\lambda}d\sin\theta$

Step 2: Electric fields: $E_1 = E_0 e^{i\omega t}$, $E_2 = E_0 e^{i(\omega t + \phi + \pi/2)}$, $E_3 = E_0 e^{i(\omega t + 2\phi)}$

Step 3: Resultant field: $E_R = E_0[1 + e^{i(\phi + \pi/2)} + e^{i2\phi}]$

Step 4: Intensity $I \propto |E_R|^2 = E_0^2[3 + 2\sqrt{2}\cos(\phi - \pi/4) + 2\cos(2\phi)]$

JEE Advanced 2019 Hard

Problem 2: Doppler Effect in Light with Moving Mirror

A light source of frequency f is moving towards a stationary mirror with speed v. The mirror reflects light back to the source. Find the beat frequency between incident and reflected light as measured at the source position.

🧠 Thought Process Breakdown:

Step 1 - Two Doppler shifts: Light undergoes Doppler shift twice - once when incident on mirror, once when reflected.

Step 2 - Mirror as moving observer then moving source: For incident light, mirror acts as moving observer. For reflected light, mirror acts as moving source.

Key Insight: Relativistic Doppler formula must be used for light

Step 3 - Beat frequency calculation: Difference between reflected frequency (as measured at source) and original frequency.

📝 Solution Approach:

Step 1: Frequency received by mirror (moving observer): $f_1 = f\sqrt{\frac{c+v}{c-v}}$

Step 2: Frequency reflected back to source (mirror as moving source): $f_2 = f_1\sqrt{\frac{c+v}{c-v}} = f\left(\frac{c+v}{c-v}\right)$

Step 3: Beat frequency: $f_{beat} = f_2 - f \approx \frac{2v}{c}f$ (for v << c)

JEE Advanced 2017 Hard

Problem 3: Polarization + Interference Combination

In Young's double slit experiment, the slits are covered with polarizers whose transmission axes make angles θ and (θ+45°) with the vertical. An analyzer is placed in front of the screen making an angle φ with the vertical. Find the intensity variation on the screen.

🧠 Thought Process Breakdown:

Step 1 - Components through analyzer: Resolve electric fields from both slits along the analyzer's transmission axis.

Step 2 - Coherence consideration: Since light is polarized differently from two slits, check if they can interfere.

Key Concept: Only parallel components of electric field can interfere

Step 3 - Intensity calculation: Standard interference pattern modified by Malus' law factors.

📝 Solution Approach:

Step 1: Components through analyzer: $E_1 = E_0\cos(\theta-\phi)$, $E_2 = E_0\cos(\theta+45°-\phi)$

Step 2: Resultant intensity: $I = I_1 + I_2 + 2\sqrt{I_1I_2}\cos\delta$

Step 3: Where $I_1 = I_0\cos^2(\theta-\phi)$, $I_2 = I_0\cos^2(\theta+45°-\phi)$, and $\delta$ is phase due to path difference

Step 4: Visibility depends on the angle between polarization directions

🚀 Advanced Problem-Solving Framework

For Multi-Concept Problems:

  • Identify all physics concepts involved
  • Break into sequential steps
  • Check consistency at each stage
  • Verify dimensional analysis

Wave Optics Specific:

  • Always use electric field approach for interference
  • Remember phase changes on reflection
  • Check polarization state for interference
  • Use small angle approximations wisely

Problems 4-5 Available in Full Version

Includes diffraction grating with missing orders and Young's experiment with medium changes

📝 Quick Self-Test

Try these conceptual questions to test your wave optics understanding:

1. Why don't two independent light sources produce interference patterns?

2. In Young's experiment, what happens to fringe width when the entire setup is immersed in water?

3. Explain why diffraction effects are more pronounced for sound than light in everyday life.

Ready to Master All 5 Problem Types?

Get complete access to all problems with step-by-step video solutions and advanced strategies

More Physics Topics