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Wave Optics Reading Time: 12 min Essential for JEE

Why Does a Prism Disperse Light? The Science of Rainbow Creation

Discover how white light splits into beautiful colors through the magic of dispersion, angular separation, and pure spectrum formation.

1666
Newton's Discovery
7
VIBGYOR Colors
2-3
JEE Marks
100%
Conceptual

The Magic Behind the Colors

When Isaac Newton first passed sunlight through a prism in 1666, he unlocked one of physics' most beautiful phenomena - dispersion. But what exactly causes white light to separate into the vibrant colors of VIBGYOR?

🎯 JEE Relevance

Dispersion appears in every JEE paper, often as 2-3 mark questions testing conceptual understanding of refractive index dependence on wavelength and angular dispersion calculations.

1. The Fundamental Concept: What is Dispersion?

Definition

Dispersion is the phenomenon of splitting of white light into its constituent colors when it passes through a transparent medium.

🌈 Simple Analogy

Think of white light as a team of 7 runners (VIBGYOR colors) with different speeds. When they enter a muddy field (the prism), faster runners (violet) get slowed down more than slower runners (red), causing them to spread out.

Newton's Classic Experiment

Setup

Apparatus: Glass prism, white light source, screen

Observation: White light enters → Color spectrum emerges

Color Order: Red, Orange, Yellow, Green, Blue, Indigo, Violet

White Light → |Prism| → VIBGYOR Spectrum

Key Discovery

Newton proved that:

  • Different colors have different refractive indices in the same medium
  • Violet light bends the most, red light bends the least
  • Colors are property of light, not property of prism

2. The Heart of Dispersion: Refractive Index & Wavelength

Cauchy's Formula

The refractive index (μ) of a material depends on the wavelength (λ) of light according to Cauchy's formula:

Cauchy's Formula

$$ \mu = A + \frac{B}{\lambda^2} + \frac{C}{\lambda^4} + \cdots $$

Where A, B, C are material constants and λ is wavelength

What This Means

Since B is positive for most materials, μ decreases as λ increases. Therefore:

Red Light (λ ≈ 700 nm)

Long wavelength → Smaller μ → Less bending

Violet Light (λ ≈ 400 nm)

Short wavelength → Larger μ → More bending

Why Different Refractive Indices?

The Physics Behind It

When light enters a medium:

  • Light waves interact with electrons in the material
  • Electrons oscillate and re-radiate light
  • This interaction depends on frequency (color)
  • Higher frequency (violet) → Stronger interaction → Slower speed → Higher μ
  • Lower frequency (red) → Weaker interaction → Faster speed → Lower μ

Mathematical Relationship

From electromagnetic theory:

$$ \mu = \frac{c}{v} $$

Where c = speed in vacuum, v = speed in medium

Since violet light travels slower in glass than red light:

$v_{violet} < v_{red}$ ⇒ $μ_{violet} > μ_{red}$

3. Angular Dispersion: The Color Separation

Definition

Angular dispersion is the angular separation between extreme colors (red and violet) of the spectrum.

Angular Dispersion Formula

$$ \theta = A(\mu_V - \mu_R) $$
$\theta$ = Angular dispersion
A = Angle of prism
$\mu_V, \mu_R$ = Refractive indices

Derivation & Understanding

For Small Angle Prism

Using prism formula for small angles:

Deviation for red light: $\delta_R = A(\mu_R - 1)$

Deviation for violet light: $\delta_V = A(\mu_V - 1)$

Angular dispersion: $\theta = \delta_V - \delta_R = A(\mu_V - \mu_R)$

Numerical Example

Given: Prism angle A = 60°, $\mu_V = 1.665$, $\mu_R = 1.645$

Calculate: Angular dispersion θ

$\theta = A(\mu_V - \mu_R) = 60° × (1.665 - 1.645) = 60° × 0.02 = 1.2°$

The red and violet rays are separated by 1.2 degrees.

💡 Key Insight

Angular dispersion depends on:

  • Prism angle (A) - Larger angle → More dispersion
  • Material property ($\mu_V - \mu_R$) - Larger difference → More dispersion
  • It's independent of the size of prism - Only shape matters!

4. Pure Spectrum: Perfect Color Separation

What is a Pure Spectrum?

A pure spectrum is one in which colors are perfectly separated without overlapping. Each wavelength appears as a distinct, sharp image.

🔬 Comparison

✓ Pure Spectrum

  • Colors don't overlap
  • Sharp boundaries
  • Each λ has unique position
  • Requires special setup

✗ Impure Spectrum

  • Colors overlap
  • Fuzzy boundaries
  • Mixed colors appear
  • Simple prism gives this

Creating a Pure Spectrum

Apparatus Setup

  1. Slit: Narrow slit to get parallel beam
  2. Collimating Lens: Makes light rays parallel
  3. Prism: At minimum deviation position
  4. Telescope: To view the spectrum

Why This Setup Works

  • Narrow slit → Each color comes from specific direction
  • Parallel rays → Each color focuses at unique point
  • Minimum deviation → Symmetric path reduces aberrations
  • Telescope focusing → Sharp image formation

🎯 JEE Application

Questions often ask:

  • "Why does a simple prism not give pure spectrum?"
  • "What modifications are needed for pure spectrum?"
  • "Calculate angular dispersion for given parameters"
  • "Compare refractive indices for different colors"

🌈 Nature's Prism: How Rainbows Form

In Raindrops

  • Water droplets act as tiny prisms
  • Light refracts, reflects internally, refracts again
  • Different colors emerge at different angles
  • Red appears at 42°, violet at 40° from anti-solar point

Key Differences from Prism

  • Rainbow has red on top, violet at bottom
  • Prism gives violet on top, red at bottom
  • Rainbow involves total internal reflection
  • Secondary rainbow has reversed colors

📋 Quick Revision Guide

Key Formulas

  • Cauchy's formula: $\mu = A + \frac{B}{\lambda^2}$
  • Angular dispersion: $\theta = A(\mu_V - \mu_R)$
  • Dispersive power: $\omega = \frac{\mu_V - \mu_R}{\mu_Y - 1}$
  • Deviation: $\delta = A(\mu - 1)$ (small angles)

Must Remember

  • Violet bends most (highest μ)
  • Red bends least (lowest μ)
  • Angular dispersion ∝ prism angle
  • Pure spectrum needs parallel rays

🎯 Practice Problems

1. A prism of angle 60° has μ₍ᵥ₎ = 1.5 and μ₍ᵣ₎ = 1.48. Calculate angular dispersion.

Hint: Use θ = A(μᵥ - μᵣ)

2. Why does violet light deviate more than red light in a prism?

Hint: Think about refractive index dependence on wavelength

3. What modifications are needed to obtain pure spectrum from a prism?

Hint: Consider slit, collimating lens, and telescope

Mastered Prism Dispersion?

You now understand the beautiful physics behind rainbows and color separation!