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Ray Optics Reading Time: 18 min Detailed Comparison

Microscope vs. Telescope: A Detailed Comparison for JEE

Master the key differences in ray diagrams, magnifying power formulas, and adjustments for normal vs. relaxed vision.

2-3
Questions per JEE
100%
Concept Clarity
6
Key Formulas
4
Adjustment Types

Why This Comparison Matters for JEE

Microscopes and telescopes are frequently asked together in JEE to test your understanding of optical instruments. Students often confuse their working principles, formulas, and adjustments.

🎯 JEE Exam Pattern

Expect 1-2 questions from optical instruments in every JEE paper. Mastering this comparison can secure 4-8 easy marks and help you avoid common pitfalls.

1. Fundamental Differences

Purpose and Function

Parameter Microscope Telescope
Purpose Viewing very small nearby objects Viewing distant objects
Object Distance Just beyond focal length of objective At infinity
Final Image At distinct vision (25 cm) or infinity At infinity or distinct vision
Focal Lengths $f_o$ small, $f_e$ small $f_o$ large, $f_e$ small
Aperture Small Large

💡 Memory Aid

"Micro" = Small objects, Small focal lengths
"Tele" = Distant objects, Large objective focal length

2. Ray Diagrams Comparison

Compound Microscope

Ray Diagram (Normal Adjustment)

[Microscope Ray Diagram]

Key Points:

  • Object placed just beyond $f_o$ of objective
  • Objective forms real, inverted, magnified image
  • This image acts as object for eyepiece
  • Eyepiece acts as simple microscope
  • Final image at infinity (normal adjustment)

Astronomical Telescope

Ray Diagram (Normal Adjustment)

[Telescope Ray Diagram]

Key Points:

  • Distant object at infinity
  • Objective forms real image at its focal plane
  • This image acts as object for eyepiece
  • Eyepiece placed so final image at infinity
  • $f_o$ + $f_e$ = length of telescope

3. Magnifying Power Formulas

Compound Microscope Formulas

When final image at infinity:

$$M = \frac{v_o}{u_o} \times \frac{D}{f_e}$$

Where:
$v_o$ = image distance from objective
$u_o$ = object distance from objective
$D$ = least distance of distinct vision (25 cm)
$f_e$ = focal length of eyepiece

When final image at D:

$$M = \frac{v_o}{u_o} \left(1 + \frac{D}{f_e}\right)$$

Approximately:
$$M \approx \frac{L}{f_o} \times \frac{D}{f_e}$$
Where $L$ = tube length

Astronomical Telescope Formulas

When final image at infinity (Normal Adjustment):

$$M = \frac{f_o}{f_e}$$

Where:
$f_o$ = focal length of objective
$f_e$ = focal length of eyepiece
Length of telescope = $f_o + f_e$

When final image at D:

$$M = \frac{f_o}{f_e} \left(1 + \frac{f_e}{D}\right)$$

Length of telescope:
$$L = f_o + u_e$$
Where $u_e$ = object distance for eyepiece

🎯 JEE Formula Strategy

  • Microscope: Remember both cases (infinity and D)
  • Telescope: $M = \frac{f_o}{f_e}$ for normal adjustment is most important
  • Sign Convention: All measurements are positive for optical instruments
  • Approximations: Often $u_o \approx f_o$ for microscope calculations

4. Adjustments for Different Vision Conditions

Normal vs. Relaxed Vision

Condition Microscope Telescope
Normal Adjustment
(Final image at infinity)

• Eyepiece adjusted so final image at infinity

• Less strain on eyes

• $M = \frac{v_o}{u_o} \times \frac{D}{f_e}$

• Final image at infinity

• $f_o + f_e$ = tube length

• $M = \frac{f_o}{f_e}$

Relaxed Vision
(Final image at D = 25 cm)

• Final image at least distance of distinct vision

• Higher magnification

• $M = \frac{v_o}{u_o} \left(1 + \frac{D}{f_e}\right)$

• Final image at D = 25 cm

• Tube length increases

• $M = \frac{f_o}{f_e} \left(1 + \frac{f_e}{D}\right)$

Microscope Adjustment Steps

  1. Place object just beyond $f_o$ of objective
  2. Adjust objective to get real, magnified image
  3. For normal vision: Adjust eyepiece so final image at infinity
  4. For maximum magnification: Adjust eyepiece so final image at D
  5. Use rack and pinion for fine adjustments

Telescope Adjustment Steps

  1. Point telescope towards distant object
  2. Adjust objective to get real image at its focal plane
  3. For normal vision: Place eyepiece so final image at infinity
  4. For maximum magnification: Adjust eyepiece so final image at D
  5. Use focusing knob for sharp image

⚠️ Common JEE Mistakes to Avoid

Mistake 1: Confusing Magnifying Power Formulas

Using telescope formula for microscope or vice versa. Remember: Microscope deals with small nearby objects, Telescope with distant objects.

Mistake 2: Wrong Sign Convention

Applying Cartesian sign convention to optical instruments. In optical instruments, all distances are taken as positive.

Mistake 3: Confusing Adjustments

Mixing up normal and relaxed vision conditions. Remember: Normal = image at infinity, Relaxed = image at D (25 cm).

📋 Quick Revision Sheet

Microscope Key Points

  • For viewing small nearby objects
  • $f_o$ and $f_e$ both small
  • Object just beyond $f_o$
  • Normal: $M = \frac{v_o}{u_o} \times \frac{D}{f_e}$
  • Relaxed: $M = \frac{v_o}{u_o} \left(1 + \frac{D}{f_e}\right)$

Telescope Key Points

  • For viewing distant objects
  • $f_o$ large, $f_e$ small
  • Object at infinity
  • Normal: $M = \frac{f_o}{f_e}$, $L = f_o + f_e$
  • Relaxed: $M = \frac{f_o}{f_e} \left(1 + \frac{f_e}{D}\right)$

🎯 Exam Tips

  • Always specify which adjustment you're considering
  • Draw quick ray diagrams for better understanding
  • Remember D = 25 cm for least distance of distinct vision
  • Practice numericals with both adjustment conditions

🎯 Practice Problems

Problem 1: A compound microscope has objective and eyepiece of focal lengths 2 cm and 5 cm respectively. The tube length is 20 cm. Calculate magnifying power when final image is at infinity.

Hint: Use $M = \frac{L}{f_o} \times \frac{D}{f_e}$ with D = 25 cm

Problem 2: An astronomical telescope has objective of focal length 100 cm and eyepiece of focal length 5 cm. Calculate length of telescope and magnifying power in normal adjustment.

Hint: $M = \frac{f_o}{f_e}$, $L = f_o + f_e$

Problem 3: Compare the magnifying power of a microscope when final image is at infinity vs at D = 25 cm.

Hint: Ratio = $\frac{1 + \frac{D}{f_e}}{\frac{D}{f_e}}$

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