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JEE Chemistry Focus Reading Time: 15 min 2 Key Reactions

Friedel-Crafts Reactions: The Power and The Limitations

Master alkylation and acylation mechanisms with carbocation rearrangements, polyalkylation issues, and deactivating group limitations.

2
Key Reactions
100%
JEE Relevance
3
Major Limitations
20min
Practice Time

Why Friedel-Crafts Reactions Matter in JEE

Friedel-Crafts reactions are fundamental electrophilic aromatic substitution reactions that appear frequently in JEE examinations. Understanding their mechanisms and limitations is crucial for:

  • Mechanism-based questions (JEE Main & Advanced)
  • Predicting reaction products with rearrangements
  • Understanding limitations for synthetic planning
  • Differentiating between alkylation and acylation
Reaction 1 Fundamental

Friedel-Crafts Alkylation

Ar-H + R-X + AlCl₃ → Ar-R + HX

(Where R-X is alkyl halide, Ar-H is aromatic compound)

⚗️ Mechanism Steps:

Step 1: Generation of Electrophile

R-X + AlCl₃ → R⁺ + [AlCl₄]⁻

Lewis acid AlCl₃ polarizes R-X bond, creating carbocation

Step 2: Electrophilic Attack

Ar-H + R⁺ → Ar-R-H⁺ (arenium ion intermediate)

Step 3: Deprotonation

Ar-R-H⁺ + [AlCl₄]⁻ → Ar-R + AlCl₃ + HCl

Base removes proton to restore aromaticity

🎯 JEE Application Example:

Problem: Predict the product when benzene reacts with CH₃-CH₂-Cl in presence of AlCl₃

Solution:

Benzene + CH₃CH₂Cl + AlCl₃ → Ethylbenzene

C₆H₆ + CH₃CH₂Cl → C₆H₅-CH₂CH₃
Reaction 2 Important

Friedel-Crafts Acylation

Ar-H + R-CO-X + AlCl₃ → Ar-CO-R + HX

(Where R-CO-X is acid chloride, forms ketone product)

⚗️ Mechanism Steps:

Step 1: Acylium Ion Formation

R-CO-Cl + AlCl₃ → R-C≡O⁺ + [AlCl₄]⁻

Forms stable acylium ion resonance structure

Step 2: Electrophilic Substitution

Ar-H + R-C≡O⁺ → Ar-CO-R-H⁺ (arenium ion)

Step 3: Regeneration of Catalyst

Ar-CO-R-H⁺ + [AlCl₄]⁻ → Ar-CO-R + AlCl₃ + HCl

🎯 JEE Application Example:

Problem: What product forms when benzene reacts with CH₃COCl in presence of AlCl₃?

Solution:

Benzene + CH₃COCl + AlCl₃ → Acetophenone

C₆H₆ + CH₃COCl → C₆H₅-CO-CH₃
Key Limitations Critical

Major Limitations of Friedel-Crafts Reactions

🚫 1. Carbocation Rearrangement

Problem: Primary carbocations can rearrange to more stable secondary/tertiary carbocations

Example: 1-Chloropropane with benzene gives isopropyl benzene instead of n-propyl benzene

CH₃-CH₂-CH₂⁺ → CH₃-CH⁺-CH₃ (more stable 2° carbocation)

Results in unexpected product formation

🚫 2. Polyalkylation

Problem: Alkylated products are more reactive than starting material

Result: Multiple substitutions occur, giving mixture of mono-, di-, and tri-substituted products

Benzene → Toluene → Xylene → Mesitylene

Electron-donating alkyl groups activate ring for further substitution

🚫 3. Deactivating Groups Prevent Reaction

Problem: Strong electron-withdrawing groups deactivate benzene ring

Groups that prevent reaction: -NO₂, -CN, -SO₃H, -COOH, -CHO, -COR

Nitrobenzene does not undergo Friedel-Crafts reaction

-NO₂ group strongly deactivates ring towards electrophilic substitution

🚀 Problem-Solving Strategies

For Alkylation vs Acylation:

  • Acylation doesn't have rearrangement issues
  • Acylation gives only mono-substituted product
  • Alkylation can use alcohols and alkenes too
  • Remember the catalyst (AlCl₃) is required

JEE Exam Tips:

  • Always check for possible rearrangements
  • Identify deactivating groups first
  • Predict polyalkylation products when relevant
  • Practice mechanism writing for both reactions

Advanced Applications Available

Includes Clemmensen reduction, Gattermann-Koch reaction, and JEE Advanced level problems

📝 Quick Self-Test

Try these JEE-level problems to test your understanding:

1. Predict the major product when benzene reacts with CH₃-CH₂-CH₂-Cl + AlCl₃

2. Why does nitrobenzene not undergo Friedel-Crafts reaction?

3. Compare and contrast Friedel-Crafts alkylation and acylation

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